std::literals::chrono_literals::operator""y
|   Defined in header  <chrono>
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|   constexpr std::chrono::year operator ""y(unsigned long long y) noexcept;  | 
(1) | (since C++20) | 
Forms a std::chrono::year literal representing a year in the proleptic Gregorian calendar.
Parameters
| y | - | the year value | 
Return value
A std::chrono::year initialized from int(y). If y > 32767, the stored value is unspecified.
Possible implementation
constexpr std::chrono::year operator ""y(unsigned long long y) noexcept { return std::chrono::year(int(y)); }  | 
Notes
This operator is declared in the namespace std::literals::chrono_literals, where both literals and chrono_literals are inline namespaces. Access to this operator can be gained with using namespace std::literals, using namespace std::chrono_literals, and using namespace std::literals::chrono_literals.
In addition, within the namespace std::chrono, the directive using namespace literals::chrono_literals; is provided by the standard library, so that if a programmer uses using namespace std::chrono; to gain access to the classes in the chrono library, the corresponding literal operators become visible as well.
Example
| This section is incomplete Reason: no example  | 
See also
  constructs a year (public member function of std::chrono::year)  |