std::is_compound
From cppreference.com
                    
                                        
                    
                    
                                                            
                    |   Defined in header  <type_traits>
  | 
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|   template< class T > struct is_compound;  | 
(since C++11) | |
If T is a compound type (that is, array, function, object pointer, function pointer, member object pointer, member function pointer, reference, class, union, or enumeration, including any cv-qualified variants), provides the member constant value equal true. For any other type, value is false.
Template parameters
| T | - | a type to check | 
Helper variable template
|   template< class T > inline constexpr bool is_compound_v = is_compound<T>::value;  | 
(since C++17) | |
Inherited from std::integral_constant
Member constants
|    value [static]  | 
   true if  T is a compound type , false otherwise  (public static member constant)  | 
Member functions
|    operator bool  | 
   converts the object to bool, returns value  (public member function)  | 
|    operator() (C++14)  | 
   returns value  (public member function)  | 
Member types
| Type | Definition | 
  value_type
 | 
  bool
 | 
  type
 | 
std::integral_constant<bool, value> | 
Notes
Compound types are the types that are constructed from fundamental types. Any C++ type is either fundamental or compound.
Possible implementation
template< class T > struct is_compound : std::integral_constant<bool, !std::is_fundamental<T>::value> {};  | 
Example
Run this code
Output:
T is compound T is not a compound
See also
|    (C++11)  | 
   checks if a type is a fundamental type   (class template)  | 
|    (C++11)  | 
   checks if a type is a scalar type   (class template)  | 
|    (C++11)  | 
   checks if a type is an object type   (class template)  | 
|    (C++11)  | 
   checks if a type is an array type   (class template)  |