std::is_copy_assignable, std::is_trivially_copy_assignable, std::is_nothrow_copy_assignable
|   Defined in header  <type_traits>
  | 
||
|   template< class T > struct is_copy_assignable;  | 
(1) | (since C++11) | 
|   template< class T > struct is_trivially_copy_assignable;  | 
(2) | (since C++11) | 
|   template< class T > struct is_nothrow_copy_assignable;  | 
(3) | (since C++11) | 
T is not a referenceable type (i.e., possibly cv-qualified void or a function type with a cv-qualifier-seq or a ref-qualifier), provides a member constant value equal to false. Otherwise, provides a member constant value equal to std::is_assignable<T&, const T&>::value.T shall be a complete type, (possibly cv-qualified) void, or an array of unknown bound. Otherwise, the behavior is undefined.
If an instantiation of a template above depends, directly or indirectly, on an incomplete type, and that instantiation could yield a different result if that type were hypothetically completed, the behavior is undefined.
Helper variable templates
|   template< class T > inline constexpr bool is_copy_assignable_v = is_copy_assignable<T>::value;  | 
(since C++17) | |
|   template< class T > inline constexpr bool is_trivially_copy_assignable_v = is_trivially_copy_assignable<T>::value;  | 
(since C++17) | |
|   template< class T > inline constexpr bool is_nothrow_copy_assignable_v = is_nothrow_copy_assignable<T>::value;  | 
(since C++17) | |
Inherited from std::integral_constant
Member constants
|    value [static]  | 
   true if  T is copy-assignable, false otherwise  (public static member constant)  | 
Member functions
|    operator bool  | 
   converts the object to bool, returns value  (public member function)  | 
|    operator() (C++14)  | 
   returns value  (public member function)  | 
Member types
| Type | Definition | 
  value_type
 | 
  bool
 | 
  type
 | 
std::integral_constant<bool, value> | 
Possible implementation
template< class T> struct is_copy_assignable : std::is_assignable< typename std::add_lvalue_reference<T>::type, typename std::add_lvalue_reference<const T>::type> {}; template< class T> struct is_trivially_copy_assignable : std::is_trivially_assignable< typename std::add_lvalue_reference<T>::type, typename std::add_lvalue_reference<const T>::type> {}; template< class T> struct is_nothrow_copy_assignable : std::is_nothrow_assignable< typename std::add_lvalue_reference<T>::type, typename std::add_lvalue_reference<const T>::type> {};  | 
Notes
The trait std::is_copy_assignable is less strict than CopyAssignable because it does not check the type of the result of the assignment (which, for a CopyAssignable type, must be an lvalue of type T) and does not check the semantic requirement that the argument expression remains unchanged. It also does not check that T satisfies MoveAssignable, which is required of all CopyAssignable types.
Example
#include <iostream> #include <utility> #include <type_traits> struct Foo { int n; }; int main() { std::cout << std::boolalpha << "Foo is trivially copy-assignable? " << std::is_trivially_copy_assignable<Foo>::value << '\n' << "int[2] is copy-assignable? " << std::is_copy_assignable<int[2]>::value << '\n' << "int is nothrow copy-assignable? " << std::is_nothrow_copy_assignable<int>::value << '\n'; }
Output:
Foo is trivially copy-assignable? true int[2] is copy-assignable? false int is nothrow copy-assignable? true
See also
|    (C++11)(C++11)(C++11)  | 
   checks if a type has a assignment operator for a specific argument   (class template)  | 
|    (C++11)(C++11)(C++11)  | 
   checks if a type has a move assignment operator   (class template)  |